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0.08x^2-18x-0.05=0
a = 0.08; b = -18; c = -0.05;
Δ = b2-4ac
Δ = -182-4·0.08·(-0.05)
Δ = 324.016
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-\sqrt{324.016}}{2*0.08}=\frac{18-\sqrt{324.016}}{0.16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+\sqrt{324.016}}{2*0.08}=\frac{18+\sqrt{324.016}}{0.16} $
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